Learn by Hamming



Finding Velocity Factor of Unknown Coax

[This topic was originally discussed at the May 2024 Fox Cities Amateur Radio Club meeting.]

For those who missed, the Tech Tip at the May club meeting was determining the velocity factor of an unknown piece of coaxial cable. For those who didnโ€™t, you missed one of Chrisโ€™ (N9CVR) famous math errors. We worked a piece of coax out to be 116% velocity factor!

In attempt to redeem the error, here goes another attempt! Chris has a piece of 50-ohm coax which is 16.9ft long. It is unmarked. If we want to use it for normal station use, its electrical length doesnโ€™t really matter. However, there exist applications where its length very much matters!

Larry WA9TT showed one such example. He needed a signal from one of four antennas to arrive at a switching box at exactly the same time. This switching box would then show the operator the direction a signal was coming from.

For the demonstration, Chris used a Jim Williams Pulse Generator (Andy AJ9L had presented about this about a year ago) and an oscilloscope. He connected a tee to the scope. The tee connected to the pulse generator and to one end of the coax. The resulting scope trace looked like this:

A screenshot of an oscilloscope trace showing 39 nanoseconds between pulses

This is called time-domain reflectometry. You can do similar in a large room with a stopwatch by clapping and listening for the echo of the clap. The pulse generator creates the equivalent of a clap, which travels down the coax, and bounces back off the end, into the oscilloscope.

The left pulse came from the pulse generator, and the smaller right pulse was a reflection from the end of the coax. Total time from the pulse to its reflection is 39.9 nanoseconds.

Hereโ€™s where the math comes in โ€“ Electricity theoretically travels at the speed of light โ€“ about 300 million meters per second. Using this information, we can calculate the coaxโ€™ apparent length:

L_{app} = \frac{299,792,458[m/s] \times 0.398 [\mu s]}{2\times 10^{6}[\mu s]} = 5.891 [m] = 19.623[ft]

But we measured the coax to be 16.9ft long.

VF [\%] = \frac{L_{act}}{L_{app}} \times 100 [\%] = \frac{16.9[ft]}{19.6[ft]} \times 100 [\%] = 86.2 [\%]

Hopefully this little math trick helps you next time youโ€™re building an antenna or trying to identify a random unmarked piece of transmission line!